When the oscillation of a diaphragm coincids with the
antinode (greatest amplitude) of a satanding wave, the standing wave is in a
normal mode. Normal Modes occur
wherever there are standing waves, such as the ones on a vibrating string or in
the pipes of an organ.
Suppose you have the closed-tube setup “The setup: Getting
identical waves going in opposite directions.” You set a speaker to make a pure
tone with wavelenght that makes a standing wave in the tube, which has an
antinode at the diaphragm . The iscukkation of the diaphragm with the antinode
of the standing wave, so it’s in a normal mode.
Standing waves are in a normal mode when the speaker makes a
soind with wavelenght

,
which is given by
(n=1,3,5,…)
Where L is the
lenght of the tube and n is a whole
number that labels the various normal modes.
The frequencies of normal modes of vibratuib are called harmonics. The first harmonic (n=1) is called the fundamental frequency. Musicians often call the
frequencies the higher frequency modes overtones.
Note that n must
be an odd number because there are an odd number of a qyarter wavelenghts from
the barrier (the closed tube) to an antinode. As n increases, so does the number of nodes and antinodes in your
normal mode. So when your speaker makes a sound with 4L, there’s only one
antinode, which is the one at the diaphragm.
The Following figure shows some normal modes of your tube-
the two lines show the two positions of maximum displacement of the normal
mode. Here, the horizontal axis measures distance from the diaphragm, and you
can see the position of the closed end of the tube on the right side of the
graph.
Now try a concrete example- what are the first notes your
tube likes to play? Suppose your tube is 0.983 meters long. The wavelenght of
its normal modes are
If the speed of sound in your tube is 343 meters per second,
then the frequencies of these modes are,
This means that the frequency of the lowest normal mode is
87.2 Hertz.
The next normal mode, when n=3, has a frequency of 262
hertz, which is about middle C on a piano. Where would you have to place your
ear in the tube in order to hear silence when you play middle C on your
speaker? You’d just have to listen at a node, which happens every
half-wavelenght from enclosed end of the tube. When n=3, your wavelenght is
given by
So you’d have to place your ear half this distance from the
closed end of the tube- that is, 0.655 meters. For this normal mode, there are
no other nodes in the tube (except, of course, the one at the closed end of the
tube), so this is the only place you’d get silence.
It turnes out that any possible vibration of sound in the
closed-tube-and-diaphragm setup is simply an interference of normal modes! So
even the craziest, most complicated, erratic vibration can be boiled down to a
matter of how much of each normal mode you have. This understanding comes from
mechanics, particles (like electron) are allowed to be only in certain
particular states. These states are like the normal modes of your tube. Like your
tube the particles can be in a state that’s an interference of these normal
modes. But when you actually measure the state of the electron, say, you can
only ever see it in one of the normal modes! This is just a hint of some of the
quantum weirdness that lies ahead for you in physics.